Question
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option B
- Let Ronit’s present age be X years. Then, father’s present age = (X + 3X) years = 4X years.
(4X + 8) = 5 (X + 8) 8X + 16 = 5X + 40 3X = 24 X = 8 2 Hence, required ratio = (4X + 16) = 48 = 2 (X + 16)
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- Let Ronit’s present age be X years. Then, father’s present age = (X + 3X) years = 4X years.
(4X + 8) = 5 (X + 8) 8X + 16 = 5X + 40 3X = 24 X = 8 2 Hence, required ratio = (4X + 16) = 48 = 2 (X + 16)
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