Question
The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages (in years)?
Answer: Option A
- Let their present ages be 4X, 7X and 9X years respectively
Then, (4X - 8) + (7X - 8) + (9X - 8) = 56
20 X = 80
X = 4
Their present ages are 16 years, 28 years and 36 years respectively
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- Let their present ages be 4X, 7X and 9X years respectively
Then, (4X - 8) + (7X - 8) + (9X - 8) = 56
20 X = 80
X = 4
Their present ages are 16 years, 28 years and 36 years respectively
Was this answer helpful ?
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