A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20

Question

A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?

Options:

A . 69.5 km/hr

B . 70 km/hr

C . 79 km/hr

D . 79.2 km/hr

Answer: Option D

Let the length of the train be x metres and its speed by y m/sec.

Then, \(\frac{x}{y} = 8 \Rightarrow x = 8y\)

Now,\(\frac{x+264}{20} = y\)

8y + 264 = 20y

y = 22.

Speed = \(22m/sec = \left(22\times\frac{18}{5}\right)km/hr = 79.2 km/hr\)

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