Question
A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:
Answer: Option B
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Let the length of the train be x metres and its speed by y m/sec.
Then,\(\frac{x}{y} = 15 \Rightarrow y = \frac{x}{15}\)
Thairfor \(\frac{x+100}{25} = \frac{x}{15}\)
15(x + 100) = 25x
15x + 1500 = 25x
1500 = 10x
x = 150 m.
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