Question
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
Answer: Option C
- Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec.
(100 + 100) = 3x 8
24x = 200
x = 25 . 3 So, speed of the faster train = 50 m/sec 3 = 50 x 18 km/hr 3 5
= 60 km/hr.
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- Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec.
(100 + 100) = 3x 8
24x = 200
x = 25 . 3 So, speed of the faster train = 50 m/sec 3 = 50 x 18 km/hr 3 5
= 60 km/hr.
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