-  (3 x 5)12 x (2 x 7)10 x (10)25 = (3 x 5)12 x (2 x 7)10 x (2 x 5)25
                                                              
                                            = 312 x 512 x 210 x 710 x 225 x 525
                                                              
                                            = 235 x 312 x 537 x 710
Total number of prime factors = (35 + 12 + 37 + 10) = 94

The number of prime factors of (3 x 5)12 (2 x 7)10 (10)25 can be calculated by the following steps:

• Prime factorization is the process of writing a number as a product of its prime factors. It is the process of breaking a composite number into its prime factors.

• The prime factors of (3 x 5)12 (2 x 7)10 (10)25 are 3, 5, 2, 7, and 10.

• We can write this number as 3^12 x 5^12 x 2^10 x 7^10 x 10^25.

• Now, we will calculate the number of prime factors.

• The number of prime factors of 3^12 = 12
• The number of prime factors of 5^12 = 12
• The number of prime factors of 2^10 = 10
• The number of prime factors of 7^10 = 10
• The number of prime factors of 10^25 = 25

• Therefore, the total number of prime factors of (3 x 5)12 (2 x 7)10 (10)25 = 12 + 12 + 10 + 10 + 25 = 94

• Hence, the correct answer is Option D. 94.