Question
Two pipes A and B can fill a tank in 15 minutes and 20 minutes respectively. Both the pipes are opened together but after 4 minutes, pipe A is turned off. What is the total time required to fill the tank?
Answer: Option D
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Part filled in 4 minutes = \(4\left(\frac{1}{15}+\frac{1}{20}\right)=\frac{7}{15}.\)
Remaining part = \(\left(1-\frac{7}{15}\right)=\frac{8}{15}\)
Part filled by B in 1 minute = \(\frac{1}{20}\)
So, \(\frac{1}{20}:\frac{8}{15}::1:x\)
x = \(\left(\frac{8}{15}\times1\times20\right)=10\frac{2}{3}min= 10min.40sec\)
So, The tank will be full in (4 min. + 10 min. + 40 sec.) = 14 min. 40 sec.
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