Question
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option B
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Increase in 10 years = (262500 - 175000) = 87500.
Increase% = \(\left(\frac{87500}{175000}\times100\right)\) %= 50%
So, Required average = \(\left(\frac{50}{10}\right)\) % = 5%
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