# Quiz

__Question:__{(481 + 426)2 - 4 x 481 x 426} = ?

**Options:**

A. | 3025 | |

B. | 4200 | |

C. | 3060 | |

D. | 3210 |

**Answer: Option A**

**(a + b) ^{2} = a^{2} + 2ab + b^{2}**

**(a - b) ^{2} = a^{2} - 2ab + b^{2}**

Here, the given statement is like (a + b)^{2} - 4ab where a= 481 and b = 426

(a + b)^{2} - 4ab = (a^{2} + 2ab + b^{2}) - 4ab = a^{2} - 2ab + b^{2} = (a - b)^{2}

Hence {(481 + 426)^{2} - 4 x 481 x 426} = (481 - 426)^{2} = 55^{2} = 3025

### 1 Comments

**JANHAVI**

(*_*)

Date : 2017-11-10 21:21:16

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### More Questions on This Topic :

**Options:**

- 5246
- 4406
- 5126
- 5776

**Answer: Option D**

**(a - b) ^{2} = a^{2} - 2ab + b^{2}**

Here, the given statement is like (a - b)^{2} + 4ab where a= 64 and b = 12

(a - b)^{2} + 4ab = (a^{2} - 2ab + b^{2}) + 4ab = a^{2} + 2ab + b^{2} = (a + b)^{2}

Hence (64 - 12)^{2} + 4 x 64 x 12 = (64 + 12)^{2} = 76^{2} = 5776

__Question 5.__If (232 + 1) is completely divisible by a whole number, which of the following numbers is completely divisible by this number?

**Options:**

- (296 + 1)
- (7 x 223 )
- (216 - 1)
- (216 + 1)

**Answer: Option A**

Let 2^{32} = x. Then (2^{32} + 1) = (x + 1)

Assume that (x + 1) is completely divisible by a whole number, N

(2^{96} + 1) = {(2^{32})^{3} + 1} = (x^{3} + 1) = (x + 1)(x^{2} - x + 1)

if (x + 1) is completely divisible by N, (x + 1)(x^{2} - x + 1) will also be divisible by N

Hence (2^{96} + 1) is completely divisible N

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