The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of

Question

The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

Options:

A . 28

B . 32

C . 40

D . 64

Answer: Option C

Let the numbers be 2x and 3x.

Then, their L.C.M. = 6x.

So, 6x = 48 or x = 8.

Therefore The numbers are 16 and 24.

Hence, required sum = (16 + 24) = 40.

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