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Question

The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:

Options:
A .  1
B .  2
C .  3
D .  4
Answer: Option B

Let the numbers 13a and 13b.


Then, 13a x 13b = 2028


 ab = 12.


Now, the co-primes with product 12 are (1, 12) and (3, 4).


[Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ]


So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4).


Clearly, there are 2 such pairs.


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