Question:

January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?

Options:
 A. Monday B. Wednesday C. Thursday D. Sunday

The year 2008 is a leap year. So, it has 2 odd days.

1st day of the year 2008 is Tuesday (Given)

So, 1st day of the year 2009 is 2 days beyond Tuesday.

Hence, it will be Thursday.

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More Questions Related to Quantitative Aptitude > Calendar And Clocks :

Question 1.

On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?

Options:
1.    Sunday
2.    Thursday
3.    Tuesday
4.    Friday

The year 2006 is an ordinary year. So, it has 1 odd day.

So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.

But, 8th Dec, 2007 is Saturday.

So, 8th Dec, 2006 is Friday.

Question 2.

Which of the following is not a leap year?

Options:
1.    700
2.    800
3.    1200
4.    2000

The century divisible by 400 is a leap year.

So,  The year 700 is not a leap year.

Question 3.

The calendar for the year 2007 will be the same for the year:

Options:
1.    2014
2.    2016
3.    2017
4.    2018

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

Year    : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017

Odd day : 1    2    1    1    1    2    1    1    1    2    1

Sum = 14 odd days $$\equiv$$ 0 odd days.

So,  Calendar for the year 2018 will be the same as for the year 2007.

Question 4.

January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?

Options:
1.    Monday
2.    Tuesday
3.    Wednesday
4.    Sunday

The year 2007 is an ordinary year. So, it has 1 odd day.

1st day of the year 2007 was Monday.

1st day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.

Question 5.

An accurate clock shows 8 oclock in the morning. Through how may degrees will the hour hand rotate when the clock shows 2 oclock in the afternoon?

Options:
1.    144º
2.    150º
3.    168º
4.    180º

Angle traced by the hour hand in 6 hours = $$\left(\frac{360}{12}\times6\right)^{0} = 180^{0}$$

Question 6.

The reflex angle between the hands of a clock at 10.25 is:

Options:
1.    180º
2.    $$192\frac{1}{2}^{0}$$
3.    195º
4.    $$197\frac{1}{2}^{0}$$

Angle traced by hour hand in  $$\frac{125}{12}$$  hrs =$$\left(\frac{360}{12}\times\frac{125}{12}\right)^{0}= 312\frac{1}{2}^{0}$$

Angle traced by minute hand in 25 min = $$\left(\frac{360}{50}\times25\right)^{0}=150^{0}$$

So, Reflex angle = 360º – $$\left( 312\frac{1}{2}^{0}-150\right)^{0}=360^{0}-162\frac{1}{2}^{0}=197\frac{1}{2}^{0}$$