__Question:__January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?

**Options:**

A. | Monday | |

B. | Wednesday | |

C. | Thursday | |

D. | Sunday |

**Answer: Option C**

The year 2008 is a leap year. So, it has 2 odd days.

1^{st} day of the year 2008 is Tuesday (Given)

So, 1^{st} day of the year 2009 is 2 days beyond Tuesday.

Hence, it will be Thursday.

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**Options:**

- Sunday
- Thursday
- Tuesday
- Friday

**Answer: Option D**

The year 2006 is an ordinary year. So, it has 1 odd day.

So, the day on 8^{th} Dec, 2007 will be 1 day beyond the day on 8^{th} Dec, 2006.

But, 8^{th} Dec, 2007 is Saturday.

So, 8^{th} Dec, 2006 is Friday.

**Options:**

- 2014
- 2016
- 2017
- 2018

**Answer: Option D**

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017

Odd day : 1 2 1 1 1 2 1 1 1 2 1

Sum = 14 odd days \(\equiv\) 0 odd days.

So, Calendar for the year 2018 will be the same as for the year 2007.

**Options:**

- Monday
- Tuesday
- Wednesday
- Sunday

**Answer: Option B**

The year 2007 is an ordinary year. So, it has 1 odd day.

1^{st} day of the year 2007 was Monday.

1^{st} day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.

__Question 5.__An accurate clock shows 8 oclock in the morning. Through how may degrees will the hour hand rotate when the clock shows 2 oclock in the afternoon?

**Options:**

- 144º
- 150º
- 168º
- 180º

**Answer: Option D**

Angle traced by the hour hand in 6 hours = \(\left(\frac{360}{12}\times6\right)^{0} = 180^{0} \)

**Options:**

- 180º
- \(192\frac{1}{2}^{0}\)
- 195º
- \(197\frac{1}{2}^{0}\)

**Answer: Option D**

Angle traced by hour hand in \(\frac{125}{12}\) hrs =\(\left(\frac{360}{12}\times\frac{125}{12}\right)^{0}= 312\frac{1}{2}^{0}\)

Angle traced by minute hand in 25 min = \(\left(\frac{360}{50}\times25\right)^{0}=150^{0}\)

So, Reflex angle = 360º – \(\left( 312\frac{1}{2}^{0}-150\right)^{0}=360^{0}-162\frac{1}{2}^{0}=197\frac{1}{2}^{0}\)

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