Quantitative Aptitude
CLOCK MCQs
Total Questions : 223
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Answer: Option C. -> Thursday
To find the day of the week on 1st January, 1987, we need to know the number of days from 1st January, 1986, to 1st January, 1987. We can then divide the number of days by 7, and the remainder will give us the day of the week on 1st January, 1987.
Explanation:We know that the year 1986 was not a leap year. Therefore, it had 365 days.
Since 1986 was not a leap year, the number of days from 1st January, 1986, to 31st December, 1986, is 365 days.
Now, we need to add 1 day to get to 1st January, 1987.
Thus, the number of days from 1st January, 1986, to 1st January, 1987, is 366.
When we divide 366 by 7, we get a remainder of 2.
Since 1st January, 1986, was a Wednesday, and there are two days left to reach the first Sunday, the 3rd day will be Friday.
Therefore, 1st January, 1987, was a Thursday.
Hence, the correct answer is option C - Thursday.
Formulae Used:
To find the day of the week on 1st January, 1987, we need to know the number of days from 1st January, 1986, to 1st January, 1987. We can then divide the number of days by 7, and the remainder will give us the day of the week on 1st January, 1987.
Explanation:We know that the year 1986 was not a leap year. Therefore, it had 365 days.
Since 1986 was not a leap year, the number of days from 1st January, 1986, to 31st December, 1986, is 365 days.
Now, we need to add 1 day to get to 1st January, 1987.
Thus, the number of days from 1st January, 1986, to 1st January, 1987, is 366.
When we divide 366 by 7, we get a remainder of 2.
Since 1st January, 1986, was a Wednesday, and there are two days left to reach the first Sunday, the 3rd day will be Friday.
Therefore, 1st January, 1987, was a Thursday.
Hence, the correct answer is option C - Thursday.
Formulae Used:
- Number of days between two dates: (number of years * 365) + number of leap years + (number of days in the remaining year)
- To check whether a year is a leap year or not:
- If the year is divisible by 4 and not divisible by 100, it is a leap year.
- If the year is divisible by 100, it is not a leap year.
- If the year is divisible by 400, it is a leap year.
Answer: Option A. -> Saturday
Answer: Option B. -> Tuesday
Answer: Option D. -> 1993
To find the year next to 1988 having the same calendar, we need to identify if 1988 is a leap year or not, as leap years have an extra day compared to non-leap years.
A leap year is a year that is exactly divisible by 4, except for years that are divisible by 100 but not by 400. For example, 1900 is not a leap year because it is divisible by 100 and not by 400, but 2000 is a leap year because it is divisible by both 100 and 400.
Now, let's determine if 1988 is a leap year or not:
1988 is divisible by 4, so it is a leap year.Since 1988 is a leap year, we know that the same calendar repeats after 28 years (i.e., 7 x 4). Therefore, we need to add 28 years to 1988 to get the year next to 1988 having the same calendar.
1988 + 28 = 2016However, 2016 is not one of the answer choices. Therefore, we need to continue adding 4 years to 2016 until we reach one of the answer choices.
2016 + 4 = 20202020 + 4 = 2024Therefore, the year next to 1988 having the same calendar is 1993, which is option D.
In summary, to find the year next to 1988 having the same calendar:
Determine if 1988 is a leap year or not.If 1988 is a leap year, add 28 years to 1988 to get the year next to 1988 having the same calendar.If the year obtained in step 2 is not one of the answer choices, continue adding 4 years until you reach one of the answer choices.If you think the solution is wrong then please provide your own solution below in the comments section .
To find the year next to 1988 having the same calendar, we need to identify if 1988 is a leap year or not, as leap years have an extra day compared to non-leap years.
A leap year is a year that is exactly divisible by 4, except for years that are divisible by 100 but not by 400. For example, 1900 is not a leap year because it is divisible by 100 and not by 400, but 2000 is a leap year because it is divisible by both 100 and 400.
Now, let's determine if 1988 is a leap year or not:
1988 is divisible by 4, so it is a leap year.Since 1988 is a leap year, we know that the same calendar repeats after 28 years (i.e., 7 x 4). Therefore, we need to add 28 years to 1988 to get the year next to 1988 having the same calendar.
1988 + 28 = 2016However, 2016 is not one of the answer choices. Therefore, we need to continue adding 4 years to 2016 until we reach one of the answer choices.
2016 + 4 = 20202020 + 4 = 2024Therefore, the year next to 1988 having the same calendar is 1993, which is option D.
In summary, to find the year next to 1988 having the same calendar:
Determine if 1988 is a leap year or not.If 1988 is a leap year, add 28 years to 1988 to get the year next to 1988 having the same calendar.If the year obtained in step 2 is not one of the answer choices, continue adding 4 years until you reach one of the answer choices.If you think the solution is wrong then please provide your own solution below in the comments section .
Answer: Option C. -> 5- Nov.
To find the solution, we need to understand the concept of the 'odd days'.
Odd Days:Odd days are the extra days that remain after we divide a number of days by seven. For example, when we divide 365 by 7, we get 52 weeks and one day left over. So, the number of odd days is one.
To find the day on a particular date, we need to know the number of days between that date and a known reference date. The reference date is usually taken as 1st January of the same year.
Now, let's use this concept to solve the given question.
We know that the day on 5th March is the same as the day on some other date of the same year. We need to find that date.
First, we need to find the number of days between 1st January and 5th March.
Number of days from 1st January to 5th March = 31 + 28 + 5 = 64 days
Now, we know that there are 2 odd days in 64 days (as 64 divided by 7 leaves a remainder of 2).
So, the day on 5th March will be 2 days ahead of the day on 1st January.
Now, we need to find the date on which the day is also 2 days ahead of 1st January.
We can start from 1st January and keep adding days until we get a date that is 2 days ahead of it.
We can do this by adding the number of days in each month until we get a total of 62 days (since 64 days will take us to 2 days ahead of 1st January).
January - 31 daysFebruary - 28 daysMarch (till 5th) - 5 days
Total = 31 + 28 + 5 = 64 days (2 odd days)
So, the day on 5th March will be the same as the day on 5th November of the same year. Therefore, the correct answer is option C.If you think the solution is wrong then please provide your own solution below in the comments section .
To find the solution, we need to understand the concept of the 'odd days'.
Odd Days:Odd days are the extra days that remain after we divide a number of days by seven. For example, when we divide 365 by 7, we get 52 weeks and one day left over. So, the number of odd days is one.
To find the day on a particular date, we need to know the number of days between that date and a known reference date. The reference date is usually taken as 1st January of the same year.
Now, let's use this concept to solve the given question.
We know that the day on 5th March is the same as the day on some other date of the same year. We need to find that date.
First, we need to find the number of days between 1st January and 5th March.
Number of days from 1st January to 5th March = 31 + 28 + 5 = 64 days
Now, we know that there are 2 odd days in 64 days (as 64 divided by 7 leaves a remainder of 2).
So, the day on 5th March will be 2 days ahead of the day on 1st January.
Now, we need to find the date on which the day is also 2 days ahead of 1st January.
We can start from 1st January and keep adding days until we get a date that is 2 days ahead of it.
We can do this by adding the number of days in each month until we get a total of 62 days (since 64 days will take us to 2 days ahead of 1st January).
January - 31 daysFebruary - 28 daysMarch (till 5th) - 5 days
Total = 31 + 28 + 5 = 64 days (2 odd days)
So, the day on 5th March will be the same as the day on 5th November of the same year. Therefore, the correct answer is option C.If you think the solution is wrong then please provide your own solution below in the comments section .
Answer: Option A. -> 7, 14, 21, 28
Answer: Option B. -> 750
Answer: Option C. -> 65
Answer: Option C. -> 1-05\(\frac{5}{11}\) o’clock
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