Question
With what minimum acceleration can a fireman slides down a rope while k breaking strength of the rope is 23 his weight
Answer: Option C
:
C
When fireman slides down, Tension in the rope T = m(g – a)
For critical condition m(g−a)=23mg⇒mg−ma=23mg∴a=g3
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:
C
When fireman slides down, Tension in the rope T = m(g – a)
For critical condition m(g−a)=23mg⇒mg−ma=23mg∴a=g3
Was this answer helpful ?
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