While finding the average of 10 given numbers, a student, by mistake, wrote 64 in place of a number 46 and got his correct average 50. The correct average of the given numbers is :
Options:
A . 48.3
B . 48.2
C . 49.3
D . 49.1
Answer: Option B Answer: (b)Difference of numbers = 64 – 46 = 18 Correct average = 50 – $18/10$ = 50 – 1.8 = 48.2 Aliter : Using Rule 26,The correct average will be = m +${\text"(a-b)"}/ \text"n"$.Here, n = 10, m = 50 a = 46, b = 64 Correct Average = m + ${\text"(a - b)"}/\text"n"$ = 50 + ${(46 – 64)}/10$= 50 -$18/10$= 50 – 1.8 = 48.2
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