There are two cases:-

(1) D,E,H,B in team X and K,G,F in team Y (total=40). So the only possible team Y is K,G,F,L,M,N and I (total=115)

(2) D,E,F in team X and K,G,H,B in team Y (total=55). So the possible addition to Y are:-

                                 a) L,M and N (total=53)

                                 b) L,M and I (total=60)

                                 c) I,M and N (total=55)

                                 d) I,L and N (total=57)
Hence answer option D