When the square of any odd number, greater than 1, is divided by 8, it always leaves remainder :
Options:
A . 1
B . 6
C . 8
D . Cannot be determined
Answer: Option A Let the number be N = 2x + 1 N2 = (2x + 1)2 = 4x2 + 1 + 4x = 4x (x + 1) + 1 Clearly, 4x (x + 1) is always divisible by 8 since one of x and (x + 1) is even which when multiplied by 4 is always divisible by 8. Hence, required remainder = 1
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