When a silver foil (Z = 47) was used in a α-ray scattering experiment, the

Question

When a silver foil (Z = 47) was used in a

α

-ray scattering experiment, the number of

α

particles scattered at

30^{\circ}

was found to be 200 per minute. If the silver foil is replaced by aluminium (z = 13) foil of same thickness, the number of

α

-particles scattered per minute at

30^{\circ}

is nearly equal to

Options:

A . 15

B . 30

C . 10

D . 20

Answer: Option A
:
A

N \propto Z^{2}

\frac{N_{2}}{N_{1}} = {[\frac{z_{2}}{z_{1}}]}^{2} = {[\frac{13}{47}]}^{2}

\frac{N_{2}}{200} = \frac{13 \times 13}{47 \times 47}

N_{2} = \frac{13 \times 13 \times 200}{47 \times 47} = 15

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