Question
#include<stdio.h>
#include<math.h>
int main()
{
printf("%f\n", sqrt(36.0));
return 0;
}
What will be the output of the program?
#include<stdio.h>
#include<math.h>
int main()
{
printf("%f\n", sqrt(36.0));
return 0;
}
Answer: Option C
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printf("%f`setminus`n", sqrt(36.0)); It prints the square root of 36 in the float format
(i.e 6.000000).
Declaration Syntax: double sqrt(double x) calculates and return the positive
square root of the given number.
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