Question
#include<stdio.h>
#include<math.h>
int main()
{
float n=1.54;
printf("%f, %f\n", ceil(n), floor(n));
return 0;
}
What will be the output of the program?
#include<stdio.h>
#include<math.h>
int main()
{
float n=1.54;
printf("%f, %f\n", ceil(n), floor(n));
return 0;
}
Answer: Option A
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ceil(x) round up the given value. It finds the smallest integer not < x.
floor(x) round down the given value. It finds the smallest integer not > x.
printf("%f, %f`setminus`n", ceil(n), floor(n)); In this line ceil(1.54) round up the 1.54 to 2
and floor(1.54) round down the 1.54 to 1.
In the printf("%f, %f`setminus`n", ceil(n), floor(n)); statement, the format specifier "%f %f"
tells output to be float value. Hence it prints 2.000000 and 1.000000.
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