Question
#include<stdio.h>
int main()
{
float d=2.25;
printf("%e,", d);
printf("%f,", d);
printf("%g,", d);
printf("%lf", d);
return 0;
}
What will be the output of the program?
#include<stdio.h>
int main()
{
float d=2.25;
printf("%e,", d);
printf("%f,", d);
printf("%g,", d);
printf("%lf", d);
return 0;
}
Answer: Option C
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printf("%e,", d); Here '%e' specifies the "Scientific Notation" format.
So, it prints the 2.25 as 2.250000e+000.
printf("%f,", d); Here '%f' specifies the "Decimal Floating Point" format.
So, it prints the 2.25 as 2.250000.
printf("%g,", d); Here '%g' "Use the shorter of %e or %f". So, it prints the
2.25 as 2.25.
printf("%lf,", d); Here '%lf' specifies the "Long Double" format. So, it prints
the 2.25 as 2.250000.
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