Question
What volume of 0.10 MH2SO4 must be added to 50 ml of a 0.10 M NaOH solution to make a solution in which the molarity of theH2SO4 is 0.050 M?
Answer: Option B
:
B
2NaOH +H2SO4⟶Na2SO4 + 2H2O
0.0025 moles ofH2SO4 will neutralise 0.005 moles NaOH.
So for 0.01 V moles H2SO4 there will be 0.01v-0.0025 moles H2SO4 left unused in the total volume(v+50ml) of solution .
The concentration here will be
0.01−0.0025v+50×1000 = 0.05M
100V−2.5V+50=0.05
100V−2.5V+50= 2.5+2.5
99.95V= 5
V= 0.05002L
V= 50.02ML
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:
B
2NaOH +H2SO4⟶Na2SO4 + 2H2O
0.0025 moles ofH2SO4 will neutralise 0.005 moles NaOH.
So for 0.01 V moles H2SO4 there will be 0.01v-0.0025 moles H2SO4 left unused in the total volume(v+50ml) of solution .
The concentration here will be
0.01−0.0025v+50×1000 = 0.05M
100V−2.5V+50=0.05
100V−2.5V+50= 2.5+2.5
99.95V= 5
V= 0.05002L
V= 50.02ML
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