Answer : Option C
Explanation :
Let sum be P
$MF#%\text{P}\left(1 + \dfrac{\text{R}}{100}\right)^\text{T} = 5458.32\\\\ \text{P}\left(1 + \dfrac{14}{100}\right)^2 = 5458.32\\\\ \text{P}\left(\dfrac{114}{100}\right)^2 = 5458.32\\\\ \text{P} = \dfrac{ 5458.32 \times 100 \times 100}{114 \times 114} = \dfrac{ 47.88 \times 100 \times 100}{114} = 0.42 \times 100 \times 100 = 4200$MF#%
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