Question
1.
#include
2.
using namespace std;
3.
int main()
4.
{
5.
char* ptr;
6.
unsigned long int a = (size_t(0) / 3);
7.
cout
What is the output of this program?
1.
#include
2.
using namespace std;
3.
int main()
4.
{
5.
char* ptr;
6.
unsigned long int a = (size_t(0) / 3);
7.
cout
Answer: Option A
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As we are dividing the zero by three, it is returning 0.
Output:
$ g++ std2.cpp
$ a.out
0
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