What is the least number of square tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
Options:
A . 840
B . 841
C . 820
D . 814
Answer: Option D Length of the room = 15 m 17 cm = 15 × 100 + 17 = 1517 cm. Breadth of the room = 9 m 2 cm = 902 cm. The HCF of the 1517 and 902 will be size of square tiles. HCF 1517 and 902 = 41 cm. Area of the room = length × breadth = 1517 × 902 cm2 Area of tiles = 41 × 41 cm2 So, number of tiles required = $$\frac{{1517 \times 902}}{{41 \times 41}}$$ = 814 tiles
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