Lakshya Education MCQs

Question: Vineet wrote a sequence of numbers in which every odd number is 7 less than the previous number, and every even number is 2 more than the previous one. The first term of the sequence is 100. Find the 5th term. [4 MARKS]
Options:

: Steps: 3 Marks

Given that:
The first term of the sequence = 100.
Now every odd number is 7 less than the previous one and every even number is 2 more than the previous one.
So the second term=100 + 2 = 102
Third term = 102 - 7 = 95
Fourth term = 95 + 2 = 97
Fifth term = 97 - 7 = 90
Hence, the fifth term of the sequence is 90.

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More Questions on This Topic :

Question 1. Find the value of the following, using suitable properties:

a) 406×516

b) 8 ×291×125

[3 MARKS]

: Steps: 1×2=2 Marks

a)By distributive law
406×516 = (400 + 6)×(500 + 16)
= 200000 + 96 + 6400 + 3000 = 2,09,496
b) By distributive law
8 ×291×125=(4×2)×(290+1)×(25× 5)=(25× 4)×(5×2)×(290+1)
= 100 × 10 × (290+1)= 1000 × (290+1)
= 290000 + 1000 = 291000
Question 2. Mahesh found a bicycle in a sale for Rs 2500 but it required a new brake cable and brake oil to make it work perfectly. He bought brake cable for Rs.82 and brake oil for Rs.20, fixed it up and then sold it to his neighbour for Rs. 3500. How much profit did he make on that deal? [4 MARKS]

: Steps: 2 Marks
Formula: 1 Mark

Mahesh bought a bicycle for Rs. 2500.
Repairing cost = Rs. (82 + 20) = 80+2+20 = 100+2 = Rs.102 Total expenses on the bicycle = Rs. (2500 + 102) = 2500+100+2 = 2600+2 = Rs.2602 Profit = (Selling Price - Cost Price) = Rs. (3500 - 2602) = 3500-2600-2 = 900-2 = Rs. 898
Question 3. Study the following number patterns:

45×9+2=407

456×9+3=4107

4567×9+4=41107

Find the next 2 lines.

[4 MARKS]

: Application: 2 Marks
Steps: 1 Mark