Two students appeared at an examination. One of them secured 9 marks more than the other and his marks were 56% of the sum of their marks. The marks obtained by them are :
Options:
A .  41, 32
B .  43, 34
C .  39, 30
D .  42, 33
Answer: Option D Answer: (d)Let the marks obtained by first student be x.Marks obtained by second student = x + 9Sum of their marks = 2x + 9As given, x + 9 = 56% of (2x + 9)x + 9 = $56/100 × (2x + 9)$$x + 9 = 14/25 × (2x + 9)$25x + 225 = 28x + 1263x = 225 – 126 ⇒ $x = 99/3 = 33$Marks obtained are 42 and 33.
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