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Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them?
Options:
A .  42, 33
B .  42, 36
C .  44, 33
D .  44, 36
Answer: Option A

Answer : Option A

Explanation :

Let the marks secured by them be x and (x + 9)
Then sum of their marks = x + (x + 9) = 2x + 9
Given that (x + 9) was 56% of the sum of their marks

$MF#%=> (x + 9) = \dfrac{56}{100} ( 2x + 9)\\\\
=> (x + 9) = \dfrac{14}{25}(2x + 9)$MF#%

=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
Then (x + 9) = 33 + 9 = 42
Hence their marks are 33 and 42



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