Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Let their marks be (x + 9) and x.
Then, x + 9 = 56 (x + 9 + x) 100
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Share this page with your friends!
Your email address will not be published. Required fields are marked *
Please Create a Free Account to continue! If you already have an account then please Login
Submit Comment/FeedBack