Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The mars obtained by them are
Let their marks be (`x + 9) and x`
Then , `x + 9 = 56/100 (x + 9 + x ) hArr 25(x +9) = 14(2x + 9) hArr 3x = 99 ``hArr x = 33`
So, their marks are 42 and 33.
Submit Comment/FeedBack