Two numbers are less t

Question

Two numbers are less than a third number by 30% and 37% respectively. How much percent is the second

number less than the first ?

Options:

A . 3%

B . 4%

C . 7%

D . 10%

Answer: Option D

Let third number be `x`

Then, first number = 70 % of `x = (7x)/(10)`; second number = 63% of `x = (63x)/(100)`

Difference = `((7x)/(10) - (63x)/(100)) = (7x)/(100)`

`:.` Required percentage = `((7x)/(100) xx (10)/(7x) xx 100)`% = 10%

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