Answer : Option B

Explanation :

Remember the following two properties of a rhombus which will be useful in solving this question
1. The sides of a rhombus are congruent.
2. The diagonals of a rhombus are unequal and bisect each other at right angles.
Let the diagonals be PR and SQ such that PR = 72 cm and SQ = 30 cm

$MF#%\begin{align}
&\text{PO = OR = }\dfrac{72}{2} = 36\text{ cm }\\\\ &\text{SO = OQ = }\dfrac{30}{2} = 15\text{ cm }\\\\ &\text{PQ = QR = RS = SP = }\sqrt{36^2 + 15^2}=\sqrt{1296 + 225}=\sqrt{1521}\text{ = 39 cm}\\\\
&\text{perimeter = 4 — 39 =156 cm}
\end{align} $MF#%