Three times the first of three consecutive odd integers is 3 more than twice the third. The integer is :
Options:
A .  9
B .  11
C .  13
D .  15
Answer: Option D Let the three integers be x, (x + 2) and (x + 4) Then, Three times the first of three consecutive odd integers is 3 more than twice the third. ⇔ 3x = 2(x + 4) + 3 ⇔ x = 11 ∴ Third integer : = x + 4 = 11 + 4 = 15
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