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Three times the first of three consecutive odd integers is 3 more than twice the third. The integer is :
Options:
A .  9
B .  11
C .  13
D .  15
Answer: Option D
Let the three integers be x, (x + 2) and (x + 4)
Then,
Three times the first of three consecutive odd integers is 3 more than twice the third.
⇔ 3x = 2(x + 4) + 3
⇔ x = 11
∴ Third integer :
= x + 4
= 11 + 4
= 15

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