**There is a square park in a society of side 7 m. What is the cost of laying bricks in the park at the rate of**

__Question:__**₹**10 / m2.

**Options:**

A. | ₹470 | |

B. | ₹440 | |

C. | ₹490 | |

D. | ₹500 |

**Answer: Option C**

: C

Total cost of laying bricks in the park= Area of the park x rate Area of a the park= (7x 7) m

^{2}= 49m

^{2}Cost = 49m

^{2}x (

**₹**10) / m

^{2}=

**₹**490

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## More Questions on This Topic :

**The area of the given figure is ____ cm2. (Both the ends are semi-circular)(All dimensions in cm and π = 22/7)**

__Question 1._____

: Area of the two semi-circles = 12(π×r2)+12(π×r2)=π×r2=227×7×7=154cm2 Area of rectangular part = length ×breadth = 10 ×14 = 140 cm2 Total area = Area of the two semi-circles + Area of the rectangle = 154+140 = 294 cm2.

**What is the radius (in cm) of the tyre in a car, if it covers 0.396 km in 300 rotations? (Use π = 227)**

__Question 2.__- 14 cm
- 21 cm
- 7 cm
- 28 cm

**Answer: Option B**

: B

The circumference of the tyre = 2πr (Distance travelled in each rotation)

Total Distance = Distance covered in 1 rotationx Number of rotations

⇒0.396=2×227×r×300

⇒r=0.396×72×22×300

Hence r =0.00021km or 21cm.

- 6 cm2
- 5 cm2
- 8 cm2
- 10 cm2

**Answer: Option A**

: A

EF divides the rectangle ABCDinto two trapeziums. Area of trapezium ABFE

=12×(Sumofparallelsides)×(Distancebetweenthem

=12×(AE+BF)×AB =12×(1+2)×4 =12×3×4=6cm2 Area of trapezium CDEF =12×(FC+ED)×CD =12×(1+2)×4 =12×3×4=6cm2 Area of both the trapeziums are equal. ∴ EF divides the rectangle ABCD in two equal parts and the area of both the parts are 6cm2.

**Puja decides to cut a circular disc into 4 equal parts. What is the perimeter of each part? (Given that the radius of the disc = 7cm, π = 227)**

__Question 4.__- 38 cm
- 25 cm
- 35 cm
- 27 cm

**Answer: Option B**

: B

When a circular discis cut into four equal parts, the perimeter of each part is more than 2πr4. This is because the length of two radii are also added to the perimeter in each part. Perimeter of each part = 2πr4+ r + r =πr2 + 2r

=22×77×2+ 2r = 11+2×7

= 11 + 14 = 25 cm

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