There is a number consisting of two digits, the digit in the units’ place is twice that in the tens’ place and if 2 be subtracted from the sum of the digits, the difference is equal to $1/6$ th of the number. The number is
Options:
A . 23
B . 26
C . 24
D . 25
Answer: Option C Answer: (c)Ten’s digit of original number = xUnit’s digit = 2xNumber = 10x + 2x = 12x According to the question, 3x – 2 = $1/6$ × 12x3x – 2 = 2x3x – 2x = 2x = 2Number = 12x = 12 × 2 = 24
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