There are six teachers. Out of them two are primary teachers and two are secondary teachers. They are to stand in a row, so as the primary teachers, middle teachers and secondary teachers are always in a set . The number of ways in which they can do so, is-
Options:
A . 52
B . 48
C . 34
D . None of these
Answer: Option B There are 2 primary teachers. They can stand in a row in P (2, 2) = 2! = 2 × 1 ways = 2 ways ∴ Two middle teachers. They can stand in a row in P (2, 2) = 2! = 2 × 1 ways = 2 ways There are two secondary teachers. They can stand in a row in P (2, 2) = 2!= 2 × 1 ways = 2 ways These three sets can be arranged themselves in 3! ways = 3 × 2 × 1 = 6 ways Hence,, the required number of ways = 2 × 2 × 2 × 6 = 48 ways
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