Question
There are 5 green, 6 black and 7 white balls in a bag. A ball is drawn at random from the bag. Find the probability that it is not white.
Answer: Option A
:
A
Given,
Number of green balls = 5
Number of black balls = 6
Number of white balls = 7
Total numberof outcomes = 5 + 6+ 7 = 18
There are 18 balls out of which 11 are not white.
⇒ Number of favourable outcomes = 11
Probability of an event, P(E)=Number of favourable outcomesTotal number of outcomes
⇒ P(balldrawn isnotwhite) = 1118
∴ Probability that the ball drawn is not white is 1118 .
Alternate Method:
P (balldrawn is white) = 718
By complementary event formula,
P( balldrawn is white) +P( balldrawn is not white) = 1
⇒ P( balldrawn is not white)
=1−P( balldrawn is white)
=1−718=1118
∴ Probability that the balldrawn is not white is 1118.
Was this answer helpful ?
:
A
Given,
Number of green balls = 5
Number of black balls = 6
Number of white balls = 7
Total numberof outcomes = 5 + 6+ 7 = 18
There are 18 balls out of which 11 are not white.
⇒ Number of favourable outcomes = 11
Probability of an event, P(E)=Number of favourable outcomesTotal number of outcomes
⇒ P(balldrawn isnotwhite) = 1118
∴ Probability that the ball drawn is not white is 1118 .
Alternate Method:
P (balldrawn is white) = 718
By complementary event formula,
P( balldrawn is white) +P( balldrawn is not white) = 1
⇒ P( balldrawn is not white)
=1−P( balldrawn is white)
=1−718=1118
∴ Probability that the balldrawn is not white is 1118.
Was this answer helpful ?
Submit Solution