There are 4 torn books in a lot consisting of 10 books. If 5 books are seleceted

Question

There are 4 torn books in a lot consisting of 10 books. If 5 books are seleceted at random what is the probability of presence of 2 torn books among the selected?

Options:

A . 13

B . 421

C . 1021

D . 27

Answer: Option C
:
C
Total Sample space:

^{10} C_{5} = 252

Favorable cases:

^{4} C_{2} \times^{6} C_{3} = 120

Hence P(E)=

\frac{120}{252} = \frac{10}{21}

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