The weight of the container alone is 25% of the container filled with a certain fluid .when some fluid is removed , the
weight of the container and remaining fluid is 50 % of the original total weight . What fractional part of the liquid has
been removed ?
Let the original total weight be `x` weight of container = `25/100 x` = `x/4`
Original weight of fluid = `(x - x/4)` = `(3x)/(4)`
New weight of (container + fluid) = `50/100 x = x/2`. New weight of fluid = `(x/2 - x/4)` = `x/4`
`:.` Required fraction = `(((3x)/(4) - (x)/(4)))/((3x)/(4))` = `x/2 xx (4)/(3x) = 2/3`
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