The volume of a right circular cylinder, 14 cm in height is equal to that of a cube whose edge is 11 cm. The radius of the base of the cylinder is :
Options:
A . 5.2 cm
B . 5.5 cm
C . 11 cm
D . 22 cm
Answer: Option B Volume of the cylinder : = Volume of the cube = (11)3 cm3 = 1331 cm3 Let the radius of the base be r cm Then, $$\eqalign{ & \frac{{22}}{7} \times {r^2} \times 14 = 1331 \cr & \Rightarrow {r^2} = \frac{{1331}}{{44}} = \frac{{121}}{4} \cr & \Rightarrow r = \frac{{11}}{2} \cr & \Rightarrow r = 5.5 \cr} $$
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