Question
The value of tan2(sec−13)+cot2(cosec−14) is
Answer: Option C
:
C
Let Sec−13=α,cosec−14=β⇒tan2α+cot2β=9−1+16−1=23
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:
C
Let Sec−13=α,cosec−14=β⇒tan2α+cot2β=9−1+16−1=23
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