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The sum of twice a number and three times of 42 is 238. What is the sum of thrice the number and two times of 42 ?
Options:
A .  245
B .  250
C .  252
D .  264
E .  None of these
Answer: Option C
Let the number be x
Then,
$$\eqalign{
& \Leftrightarrow 2x + 3 \times 42 = 238 \cr
& \Leftrightarrow 2x + 126 = 238 \cr
& \Leftrightarrow 2x = 112 \cr
& \Leftrightarrow x = 56 \cr} $$
∴ Required sum :
$$\eqalign{
& = 3x + 2 \times 42 \cr
& = 3 \times 56 + 2 \times 42 \cr
& = 168 + 84 \cr
& = 252 \cr} $$

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