Question
The sum of three consecutive numbers is 36. Find the numbers.
Answer: Option C
:
C
Let the first number be a.
So the three consecutive numbers will be a,a+1,a+2.
a +a +1 +a +2 = 36
⇒3a +3 = 36
⇒3a = 36 -3 = 33
⇒a=333=11
So, the three consecutive numbers will be 11,12,13.
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:
C
Let the first number be a.
So the three consecutive numbers will be a,a+1,a+2.
a +a +1 +a +2 = 36
⇒3a +3 = 36
⇒3a = 36 -3 = 33
⇒a=333=11
So, the three consecutive numbers will be 11,12,13.
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