The sum of the squares of three numbers is 138, while the sum of their product taken two at a time is 131. Their sum is :
Options:
A . 20
B . 30
C . 40
D . None of these
Answer: Option A Let the numbers be a, b and c. Then, a2 + b2 + c2 = 138 And (ab + bc + ca) = 131 ∴ (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) = 138 + 2 × 131 = 400 ⇒ (a + b + c) = $$\sqrt {400} $$ = 20
Submit Comment/FeedBack