The sum of the squares of 2 numbers is 146 and the square root of one of them is $√5$. The cube of the other number is
Options:
A . 1441
B . 1111
C . 1331
D . 1221
Answer: Option C Answer: (c)First number = $(√5)^2 = 5$Let the second number be x.$x^2 + 5^2 = 146$$x^2$ = 146 –25 = 121$x = √{121} = 11$Cube of 11 =1331
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