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The sum of the length breadth and depth of cuboid is 19cm and it's diagonal is 5√5 cm it's surface area is?
Options:
A .  125 Sq.cm
B .  236 Sq.cm
C .  361 Sq.cm
D .  None of these
Answer: Option B


(l+b+h) = 19 and 
=> (l+b+h) 2 =(19) 2 and (l2 +b2 +h2) = 125 
=> (l2 +b2 +h2) + 2(lb +bh+lh) = 361 and 
(l2 +b2 +h2) =125 
=> 125 + 2(lb +bh+ lh) =361 
=> 2(lb +bh+lh) =(361 -125) = 236 
Surface area = 236 SQ.cm



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