Question
The sound from a very high burst of fireworks takes 5 s to arrive at the observer. The burst occurs 1662 m above the observer and travels vertically through two stratifier layers of air, the top one of thickness
d1 at 0∘C and the bottom one of thickness d2 at 20∘C. Then (assume velocity of sound at 0∘C is 330 m/s)
d1 at 0∘C and the bottom one of thickness d2 at 20∘C. Then (assume velocity of sound at 0∘C is 330 m/s)
Answer: Option D
:
D
Time taken is given by
T=t1+t2=d1v1+d2v2V1=v∘0c=330m/sv2=(330+.06t)=342m/sd=1662m∴T=d1330+(d−d1)342=5sd1(342−330)330×342+d342=5s12d1=5(342×330)−330×1662d1=1320md2=342m
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:
D
Time taken is given by
T=t1+t2=d1v1+d2v2V1=v∘0c=330m/sv2=(330+.06t)=342m/sd=1662m∴T=d1330+(d−d1)342=5sd1(342−330)330×342+d342=5s12d1=5(342×330)−330×1662d1=1320md2=342m
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