The quantity of water (in ml) needed to reduce 9 ml shaving lotion containing 50% alcohol to a lotion containing 30% alcohol, is
Quantity of alcohol in 9 ml lotion = `(50/100 xx 9)` ml = 4.5 ml.
Let the water to be added be `x` ml.
Then, `(4.5)/(9 + x) = 330/100 hArr 270 + 30x = 450 hArr x = 6` ml.
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