Question
The product "n” of three positive integers is 6 times their sum. If one of the numbers is the sum of the other two, then the sum of all possible value(s) of "n” is?
Answer: Option A
:
A
Let the numbers be x,y, x+y.
Therefore xy(x+y) = 12(x+y). Hence, xy= 12.
So, (x,y) = (1,12), (2,6) or (3,4).
Hence "n" = 156, 96 or 84.
Sum "s" (of all possible values of n) = 336.
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:
A
Let the numbers be x,y, x+y.
Therefore xy(x+y) = 12(x+y). Hence, xy= 12.
So, (x,y) = (1,12), (2,6) or (3,4).
Hence "n" = 156, 96 or 84.
Sum "s" (of all possible values of n) = 336.
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