Question
The probability of happening an event A is 0.5 and that of B is 0.3. If A and B are mutually exclusive events, then the probability of happening neither A nor B is
Answer: Option B
:
B
P(¯¯¯¯A∩¯¯¯¯B)=P(¯¯¯¯A∪¯¯¯¯B)−1−P(A∪B)
Since A and B are mutually exclusive,
P(A∪B)=P(A)+P(B)
Hence required probability =1–(0.5+0.3)=0.2
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:
B
P(¯¯¯¯A∩¯¯¯¯B)=P(¯¯¯¯A∪¯¯¯¯B)−1−P(A∪B)
Since A and B are mutually exclusive,
P(A∪B)=P(A)+P(B)
Hence required probability =1–(0.5+0.3)=0.2
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